Exercise 1
int i = 16;
int j = 32;
int k = 8;
bool r;
1. r = (i == 16); True
2. r = (k != 16); True
3. r = (k < 10); True
4. r = (j > 33); False
5. r = (j == (k * 2)); False
6. r = (j == (i * 2)); True
7. r = ((k + i) <= (j – i)); False
8. r = ((i / k) == 2); True
9. r = ((( i + j + k ) / k ) >= 7 ); False
Exercise 2
#include <iostream>
using std::cout;
using std::cin;
int hi_score = 500;
int main()
{
int score1, score2;
cout << “Player one please input a number: ” ;
cin >> score1;
cout << “Player two please input a number: ” ;
cin >> score2;
if (score1 >= hi_score )
cout << “This score is the new high score !: ” << score1 << “\n”;
if (score2 >= hi_score )
cout << “This score is the new high score !: ” << score2;
if (score1 > score2)
cout << “Player 1’s score is higher! \n”;
if (score2> score1 )
cout << “Player 2’s score is higher! \n”;
if (score1 == score2)
cout << “Both Players had the same score! \n”;
return 0;
}
Exercise 3
#include <iostream>
using std::cout;
using std::cin;
int hi_score = 500;
int main()
{
int score1, score2;
cout << “Player one please input a number: ” ;
cin >> score1;
cout << “Player two please input a number: ” ;
cin >> score2;
if (score1 >= hi_score )
cout << “This score is the new high score !: ” << score1 << “\n”;
if (score2 >= hi_score )
cout << “This score is the new high score !: ” << score2;
if (score1 > score2)
cout << “Player 1’s score is higher! \n”;
if (score2> score1 )
cout << “Player 2’s score is higher! \n”;
if (score1 == score2)
cout << “Both Players had the same score! \n”;
return 0;
}
In my code the number for my local variable is displayed over the global variable, this is because variables inside a function take priority.
#include <iostream>
int test_number = 100;
int main()
{
int test_number = 200;
std::cout << test_number << “\n”;
std::cout << ::test_number;
return 0;
}
With this code the value for the global integer is also displayed because I used the scope resolution operator ( :: ) .
Exercise 4
#include <iostream>
using std::cout;
int main()
{
int i = 16, j = 32, k = 8;
bool r;
if (i == 16)
cout << (i == 16) << “r = (i == 16)” << ” is true \n”;
else
cout << (i == 16) << “r = (i == 16)” << ” is false \n”;
if (k != 16)
cout << (k != 16) << “r = (k != 16) is true \n”;
else
cout << (k != 16) << “r = (k != 16) is false \n”;
if (k < 20)
cout << (k < 20) << “r = (k < 20) is true \n”;
else
cout << (k < 20) << “r = (k < 20) is false \n”;
if (j > 33)
cout << (j > 33) << “r = (j > 33) is true \n”;
else
cout << (j > 33) << “r = (j > 33) is false \n”;
if (j == (k * 2))
cout << (j == (k * 2)) << “r = (j == (k * 2)) is true \n”;
else
cout << (j == (k * 2)) << “r = (j == (k * 2)) is false \n”;
if (j == (i * 2))
cout << (j == (i * 2)) << “r = (j == (i * 2)) is true \n”;
else
cout << (j == (i * 2)) << “r = (j == (i * 2)) is false \n”;
if ((k + i) <= (j – i))
cout << ((k + i) <= (j – i)) << “r = ((k + i) <= (j – i)) is true \n”;
else
cout << ((k + i) <= (j – i)) << “r = ((k + i) <= (j – i)) is false \n”;
if ((i / k) == 2)
cout << ((i / k) == 2) << “r = ((i / k)==2) is true \n”;
else
cout << ((i / k) == 2) << “r = ((i / k)==2) is false \n”;
if (((i + j + k) / k) >= 7)
cout << (((i + j + k) / k) >= 7) << “r = (((i + j + k) / k) >= 7) is true \n”;
else
cout << (((i + j + k) / k) >= 7) << “r = (((i + j + k) / k) >= 7) is false \n”;
return 0;
}
Exercise 5
If the code is run it will not display anything as there is a ; after the if statement that stops the code from running.
#include <iostream>
using namespace std;
int main()
{
if (false)
;
{
cout << “This text wont be shown.”;
}
return 0;
}
Exercise 6
If you run the code it should display “x and y are equal” onto the screen. This would run anyway as the the if statement does not use the correct operator. Instead of using (x = y) it should use (x == y).
#include <iostream>
using namespace std;
int main()
{
int x = 5;
int y = 7;
if (x = y)
{
cout << “x and y are equal.”;
}
return 0;
}
Seb Crowhurst Game Development 